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An ant walks an average of 500 meters in 12 minutes. A beetle walks 15 11 Jul 2016, 12:30
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An ant walks an average of 500 meters in 12 minutes. A beetle walks 15% less distance at the same time on the average. Assuming the beetle walks at her regular rate, what is its speed in km/h?

A. 2.125
B. 2.5
C. 2.775
D. 3.2
E. 3.5
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An ant walks an average of 500 meters in 12 minutes. A beetle walks 15 11 Jul 2016, 14:19
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Y am I getting 2.125 ?.. not even in the options. :(

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An ant walks an average of 500 meters in 12 minutes. A beetle walks 15 12 Jul 2016, 00:05
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shashanksagar
Y am I getting 2.125 ?.. not even in the options. :(

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the ant walks an average of 500 meters in 12 minutes
or,
500 meters in 1/5 hours

the beetle walks 15% less distance = 500-75=425 meters in 12 minutes
or,
0.425 km in 12/60 = 1/5 hours

speed = 0.425*5 = 2.125 km/h

I guess option A should be 2.125
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An ant walks an average of 500 meters in 12 minutes. A beetle walks 15 22 Oct 2017, 07:54
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I did a bit of dimensional analysis initially.

(500m/12 min) * (60 min/1hr) * (1km/1000m) = 5km/2hr = 2.5km/hr.

Remember that the answers are increasing in rates. Given that the beetle must be walking slower than 2.5km/hr and there is only one answer with a lower rate than 2.5km/hr, (Answer choice A) that one must be the answer.

If you had to solve for it, since we know the beetle's speed is 15% less (10% + 5%), just determine 15% and subtract from 2.5km/hr. 10% of 2.5 = 0.25,and half of that is 0.125.

Then we're looking at [2.5 - (0.25 + .125)] or (2.5 - 0.375) = 2.125 which should be the answer, but maybe it's a typo?
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An ant walks an average of 500 meters in 12 minutes. A beetle walks 15 22 Oct 2017, 09:23
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Bunuel
An ant walks an average of 500 meters in 12 minutes. A beetle walks 15% less distance at the same time on the average. Assuming the beetle walks at her regular rate, what is its speed in km/h?

A. 2.215.
B. 2.5.
C. 2.775.
D. 3.2.
E. 3.5.
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Bunuel , I, too, calculate the answer as 2.125 km/hr. I think there might be a typo in answer A.

Ant: \(\frac{500m}{12min}\)

Beetle walks 15 percent less distance in same time. (500 * .85 ) = 425 m

Beetle: \(\frac{425m}{12min} *\frac{60min}{1hr}*\\
\frac{1km}{1000m}\) =

\(\frac{425}{200}\) = 2.125 km/hr

Answer A?
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An ant walks an average of 500 meters in 12 minutes. A beetle walks 15 23 Oct 2017, 01:18
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Bunuel
An ant walks an average of 500 meters in 12 minutes. A beetle walks 15% less distance at the same time on the average. Assuming the beetle walks at her regular rate, what is its speed in km/h?

A. 2.215.
B. 2.5.
C. 2.775.
D. 3.2.
E. 3.5.
Bunuel , I, too, calculate the answer as 2.125 km/hr. I think there might be a typo in answer A.

Ant: \(\frac{500m}{12min}\)

Beetle walks 15 percent less distance in same time. (500 * .85 ) = 425 m

Beetle: \(\frac{425m}{12min} *\frac{60min}{1hr}*\\
\frac{1km}{1000m}\) =

\(\frac{425}{200}\) = 2.125 km/hr

Answer A?
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Typo edited. Thank you all.
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An ant walks an average of 500 meters in 12 minutes. A beetle walks 15 26 Oct 2017, 15:30
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Bunuel
An ant walks an average of 500 meters in 12 minutes. A beetle walks 15% less distance at the same time on the average. Assuming the beetle walks at her regular rate, what is its speed in km/h?

A. 2.125
B. 2.5
C. 2.775
D. 3.2
E. 3.5
Show more

The rate of the beetle in meters per minute is (0.85 x 500)/12 = 425/12.

Since 1 hour = 60 minutes and 1 km = 1000 meters, the rate in km per hour is:

425/12 x 60 / 1000 = 425 x 5 / 1000 = 2.125

Answer: A
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An ant walks an average of 500 meters in 12 minutes. A beetle walks 15 19 Oct 2025, 00:09
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