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100000 is the principal
3 % will be the interest rate

In 6 months, there will be 2 quarters so no. of cycle will be 2

1st cycle simple interest: 3000
2nd cycle simple interest: 3000
2nd cycle interest on 1st cycle simple interest: 90
adding all three : 6090$
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yosita18
Fiona purchased a 1-year, $1,00,000 certificate of deposit that paid interest at 12% p.a., interest being compounded quarterly. what is the expected total amount of interest which must be paid on this certificate by the end of 6 months?

(A) $5940
(B) $5000
(C) $6020
(D) $6090
(E) $5050

There might be many ways of calculating Compound Interest.
But, when I use the following formula:
A = P (1+R/C)^NC

P = Principal Amount
R = Annual Interest Rate (as a Decimal)
C = Number of "Compoundings" Per Year
N = Number of Years
A = Final Amount

Can you please help solve this question using the above formula?

Dear Moderator,
Can OA for this question please be updated, Thank you.
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stne
yosita18
Fiona purchased a 1-year, $1,00,000 certificate of deposit that paid interest at 12% p.a., interest being compounded quarterly. what is the expected total amount of interest which must be paid on this certificate by the end of 6 months?

(A) $5940
(B) $5000
(C) $6020
(D) $6090
(E) $5050

There might be many ways of calculating Compound Interest.
But, when I use the following formula:
A = P (1+R/C)^NC

P = Principal Amount
R = Annual Interest Rate (as a Decimal)
C = Number of "Compoundings" Per Year
N = Number of Years
A = Final Amount

Can you please help solve this question using the above formula?

Dear Moderator,
Can OA for this question please be updated, Thank you.

Done.

This is a copy of the following OG question: https://gmatclub.com/forum/leona-bought ... 43742.html
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Senthil1981
yosita18
Fiona purchased a 1-year, $1,00,000 certificate of deposit that paid interest at 12% p.a., interest being compounded quarterly. what is the expected total amount of interest which must be paid on this certificate by the end of 6 months?

Ans: $6090

There might be many ways of calculating Compound Interest.
But, when I use the following formula:
A = P (1+R/C)^NC

P = Principal Amount
R = Annual Interest Rate (as a Decimal)
C = Number of "Compoundings" Per Year
N = Number of Years
A = Final Amount

Can you please help solve this question using the above formula?


You've already mentioned the formula, just substitute the values.
\(A = 1,00,000 ( 1 + \frac{12}{400})^2\)
raised to 2 because the question asks for only \(\frac{1}{2}\) year and \(\frac{1}{2}*4 = 2\)
= \(10^5(1.03)^2 = 1,06,090.\)

so Interest is 1,06,090 - 1,00,000 = 6,090

Great explanation Senthil1981.
To clarify if interest after 3 months, is the year is 3/12 = 1/4? Similarily if it's 9 months, will it be 9/12 = 3/4 ?
Could you confirm? Thanks
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