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saswata4s
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saswata4s
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chetan2u
It seems you have not put the choices in order and that is why 370 is in D choice and not B..

I've updated the correct OA. Thanks for pointing out.

Cheers.
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saswata4s
Find the number of zeroes in 1142! × 348! × 17!.

(A) 369
(B) 370
(C) 371
(D) 375
(E) 385
1142 will have 228 + 45 + 9 + 1 = 283 zeo's
348 will have 69 + 13 + 2 = 84 zero's
17 will have 3 zeros

Hence, Total no of zero's will be 283 + 84 + 3 = 370 zero's, Answer must be (B)
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For the product of 1142! × 348! × 17!, the number of zeroes is determined by counting how many times 5 appears as a factor.

For 1142!:


1142/5 = 228, 1142/25 = 45, 1142/125 = 9, 1142/625 = 1 → Total = 283

For 348!:


348/5 = 69, 348/25 = 13, 348/125 = 2 → Total = 84

For 17!:


17/5 = 3 → Total = 3
Adding these gives 283 + 84 + 3 = 370.

Answer: B (370)
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