From a group of three boys and four girls, a school hallway monitor gr

Question

From a group of three boys and four girls, a school hallway monitor group is to be selected. If the group is to be formed of one boy and four girls, how many different such groups can be formed?

A. 1
B. 3
C. 36
D. 72
E. 360

BrentGMATPrepNow · Accepted Answer

Take the task of creating a hallway monitor group and break it into  stages .

Stage 1 : Select 4 girls to be in the group
Since there are only 4 girls to choose from, there's only  1  way to select 4 girls - you must select ALL of them, so there's only 1 way. 
Alternatively, we COULD say that we can select 4 girls from the 4 girls in 4C4 ways (which also equals  1 ) 
So, we can complete stage 1 in  1  way

Stage 2 : Select 1 boy to be in the group
Since there are 3 boys to choose from, we can complete stage 2 in  3  ways

By the Fundamental Counting Principle (FCP), we can complete the two stages (and thus create a 4-person hallway monitor group) in  (1)(3)  ways (= 3 ways)

Answer: B

Note: the FCP can be used to solve the MAJORITY of counting questions on the GMAT. So, be sure to learn this technique.

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naorba · Answer

I don't want to be rude :oops:

but I did not understand whether positions are considered unique or not, anyway I'll answer in both cases: In case positions are identical: we need to form a group of 5 people in which 4 of them has to be girls. we already have 4 girls so no arranging here (only 1 option for arranging). we do have 3 boys and only 1 spot for 1 boy, so 3 options for the boys - so we can form 3 groups (each group has different boy) Answer is B; In case positions are unique: let's start with the girls. let's assume that there are only 4 spots. the options for arranging the girls in those 4 spots are: 4! = 1*2*3*4 = 24 now, let's add the 5th spot. in every arrangement there will be 1 "Free" spot (not really free because one of the boys will sit there), so we can have 5 different options for free spot, therefore: 24*5=120 let's go back to the boys. remember the "free" spots? for every option with the "Free" sit, we can put 3 different boys to sit, and so the answer: 120*3 = 360 Answer is E; Waiting the OA :wink:

sobby · Answer

Answer is B
 3c1  * 4c4 =  3 * 1  = 3

RUSDI · Answer

Since the question is asking number of group, then the answer is 3 (E)
3C1 x 4C4 = 3

If the question specifies in the group one of the captain will be selected, then the answer will be 72.
(3C1 X 4C4) x (1! x 4!) = 72
Thanks

mvictor · Answer

we have 3C1 * 4C4 = 3*1 = 3.

answer is B.

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From a group of three boys and four girls, a school hallway monitor gr

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