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555-605 (Medium)|   Algebra|      
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Bunuel
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If x = 9 is one solution to the quadratic x^2 − yx + 27 = 0, what is 15 Feb 2017, 03:27
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E
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25% (medium)

Question Stats:

73% (00:55) correct 27% (00:56) wrong based on 455 sessions

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If x = 9 is one solution to the quadratic x^2 − yx + 27 = 0, what is the value of y?

A. −12
B. −3
C. 3
D. 6
E. 12
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E
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If x = 9 is one solution to the quadratic x^2 − yx + 27 = 0, what is 15 Feb 2017, 03:54
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Bunuel
If x = 9 is one solution to the quadratic x^2 − yx + 27 = 0, what is the value of y?

A. −12
B. −3
C. 3
D. 6
E. 12
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Substitute x = 9 in the Quadratic equation .
81 - 9y + 27 = 0
y = 108/9
y = 12

Answer is E .
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If x = 9 is one solution to the quadratic x^2 − yx + 27 = 0, what is 15 Feb 2017, 04:04
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Bunuel
If x = 9 is one solution to the quadratic x^2 − yx + 27 = 0, what is the value of y?

A. −12
B. −3
C. 3
D. 6
E. 12
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x^2 − yx + 27 = 0
If x = 9
81-9y+27=0
9y=108
y=12

Hence Option E is correct
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If x = 9 is one solution to the quadratic x^2 − yx + 27 = 0, what is 15 Feb 2017, 08:23
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Bunuel
If x = 9 is one solution to the quadratic x^2 − yx + 27 = 0, what is the value of y?

A. −12
B. −3
C. 3
D. 6
E. 12
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Plug in the value of x = 9 and check -

\(9^2 − 9y + 27 = 0\)

Or, \(9y = 108\)

So, y = 12

Hence, correct answer must be (E) \(y = 12\)
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If x = 9 is one solution to the quadratic x^2 − yx + 27 = 0, what is 15 Feb 2017, 16:10
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Bunuel
If x = 9 is one solution to the quadratic x^2 − yx + 27 = 0, what is the value of y?

A. −12
B. −3
C. 3
D. 6
E. 12
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we know 27 is a multiple of 9
27/9=3
we know signs of both numbers are negative
(x-9)(x-3)=x^2-12x+27=0
y=12
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If x = 9 is one solution to the quadratic x^2 − yx + 27 = 0, what is 31 May 2019, 08:27
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Bunuel
If x = 9 is one solution to the quadratic x^2 − yx + 27 = 0, what is the value of y?

A. −12
B. −3
C. 3
D. 6
E. 12
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x^2 − yx + 27 = 0
x=9
-9y=-108
y=12
IMO E
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If x = 9 is one solution to the quadratic x^2 − yx + 27 = 0, what is 03 Jul 2020, 13:05
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\(x^2 − yx + 27 = 0\)
\(9^2 − y9 + 27 = 0\)
\(9y=81+27\)
\(9y=108\)
\(y=12\)
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If x = 9 is one solution to the quadratic x^2 − yx + 27 = 0, what is 05 Jul 2020, 15:01
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Bunuel
If x = 9 is one solution to the quadratic x^2 − yx + 27 = 0, what is the value of y?

A. −12
B. −3
C. 3
D. 6
E. 12
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Solution:

Substituting x = 9 into the equation, we have:

81 - 9y + 27 = 0

9 - y + 3 = 0

12 = y

Alternate Solution:

The constant term 27 is the product of the roots of the quadratic equation, hence the other root is 27/9 = 3.

The term y is the sum of the roots of the same quadratic, hence y = 3 + 9 = 12.

Answer: E
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If x = 9 is one solution to the quadratic x^2 − yx + 27 = 0, what is 01 Jan 2024, 08:24
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Mental math. 9 is a negative. Its a case of (x- #)(x- #). The other figure is definitely 3.
-3+-9 = -12. But there's already a negative in the equation so its just 12. Easily can mess up between A and E here.
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If x = 9 is one solution to the quadratic x^2 − yx + 27 = 0, what is 04 Sep 2025, 13:49
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