GMATPrepNow
If the average (arithmetic mean) of six consecutive odd integers is 4q + 2, what is the difference between the greatest and least of the six integers?
A. 6q + 4
B. 10q
C. 6q/(q – 6)
D. 6
E. 10
Yes, the question is a bit of a trick question, since we don't really need to know the part about the average equaling 4q+2.
The range of 6 odd integers will ALWAYS be 10.
That said, we can also use that information to solve the question.
We'll use the
input-output approach.
So, let's see what happens when we analyze a random set of 6 consecutive odd integers.
How about {9, 11, 13, 15, 17, 19}
Here, the mean = 14
From the given information, this means that 4q + 2 = 14
Solve to get q =
3Now, for this set of values, the difference between the greatest and least of the six integers = 19 - 9 =
10In other words, when we INPUT q =
3, then the OUTPUT (the answer to the given question) is
10Now, we'll plug q =
3 into the 5 answer choices and see which one yields an OUTPUT of
10A. 6(
3) + 4 =
22. We need
10, so eliminate
B. 10(
3) =
30. We need
10, so eliminate
C. 6(
3)/(
3 – 6) =
-6. We need
10, so eliminate
D.
6. We need
10, so eliminate
E.
10. PERFECT MATCH
Answer: E