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vikasp99
The remainder when the positive integer m is divided by n is r. What is the remainder when 2m is divided by 2n ?

(A) r

(B) 2r

(C) 2n

(D) m – nr

(E) 2(m – nr)


We have \(m=k\times n + r\) with \(0 \leq r < n\)

Hence \(2m= k \times (2n) + 2r\). Since \(0 \leq 2r < 2n\), we could say that the remainder when \(2m\) is divided by \(2n\) is \(2r\).

The answer is B
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vikasp99
The remainder when the positive integer m is divided by n is r. What is the remainder when 2m is divided by 2n ?

(A) r

(B) 2r

(C) 2n

(D) m – nr

(E) 2(m – nr)

Plug in some numebrs and check -

m = 5
n = 3
r = 2

Quote:
What is the remainder when 2m is divided by 2n ?

2m = 10
2n = 6

So, Remainder when 2m is divided by 2n is = 4

2r = 4

Thus, answer must be (B) 2r
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best way to solve this is to insert numbers and decide.
e.g

5/2 rem. = 1

10/4 rem. = 2

17/3 rem = 2

34/6 rem. = 4

so on. hence 2r is the answer.
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Plugging number works pretty well here.
5 by 2 remainder is 1
10 by 4 remainder is 2

less than 10 secondes actually.
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vikasp99
The remainder when the positive integer m is divided by n is r. What is the remainder when 2m is divided by 2n ?

(A) r

(B) 2r

(C) 2n

(D) m – nr

(E) 2(m – nr)

let x=2m/2n remainder
we know the quotients are equal
r=m-nq
x=2m-2nq
➡x/2=m-nq
thus, x/2=r
➡x=2r
B
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We can plug in numbers and test this .
Example . Take m =10 , n= 3 , r = 1 ; m=20 , n=6 , r = 2

Take m = 7 , n =5 , r = 2 ; m =14 , n= 10 , r = 4

Answer is B .
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The remainder when the positive integer m is divided by n is r

Theory: Dividend = Divisor*Quotient + Remainder

m -> Dividend
n -> Divisor
a -> Quotient (Assume)
r -> Remainders
=> m = n*a + r = an + r ...(1)

What is the remainder when 2m is divided by 2n

2m = 2*(an + r) (from (1))
=> 2m = 2an + 2r = 2n*a + 2r
=> 2m when divided by 2n gives a as quotient and 2r as remainder

So, Answer will be B
Hope it helps!

Watch the following video to learn the Basics of Remainders

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BrentGMATPrepNow


if we use the equation 2m = 2an + 2r = 2n*a + 2r
=> 2m when divided by 2n gives a as quotient and 2r as remainder

why the 2 is not canceled out when divided by 2n, so the reminder is r?
I understand if we test numbers, the reminder is 2r, just want to learn how the equation works. Thanks!
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Emily1122

2m = 2n*a + 2r
Now if we cancel 2 from both the sides we will get

m = na + r
=> m when divided by n gives a as quotient and r as remainder, which is true.
[Note that 2m has become m now and 2n has become n]

Ex: 14 = 4*3 + 2
=> 14 when divided by 4 gives 3 as quotient and 2 as remainder

If we cancel 2 from both the sides we get
7 = 2*3 + 1
=> 7 when divided by 2 gives 3 as quotient and 1 as remainder

Hope it helps!
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