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vikasp99
For any positive integer n, n! denotes the product of all the integers from 1 through n. What is the value of 3!(7 – 2)! ?

(A) 2!
(B) 3!
(C) 5!
(D) 6!
(E) 10!


3!(7-2)!
= 6 * 5!

=6!

So OA :D
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Given that n! denotes the product of all the integers from 1 through n and we need to find the value of 3!(7 – 2)!

3!(7-2)! = 3!*5! = 1*2*3*5! = 6*5! = 6!

So, Answer will be D
Hope it helps!
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