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If a^2 -10 < 1590, then how many integer values can a have 04 Apr 2017, 04:48
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B
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60% (01:20) correct 40% (01:22) wrong based on 502 sessions

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If a^2 -10 < 1590, then how many integer values can a have?

(A) 78
(B) 79
(C) 80
(D) 81
(E) 101
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B
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If a^2 -10 < 1590, then how many integer values can a have 04 Apr 2017, 04:52
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saswata4s
If a^2 -10 < 1590, then how many integer values can a have?

(A) 78
(B) 79
(C) 80
(D) 81
(E) 101
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a^2 -10 < 1590

a^2 < 1600

-40 < a < 40.

a can take 79 integer values: 39 negative, 0 and 39 positive.

Answer: B.
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If a^2 -10 < 1590, then how many integer values can a have 21 May 2018, 16:39
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saswata4s
If a^2 -10 < 1590, then how many integer values can a have?

(A) 78
(B) 79
(C) 80
(D) 81
(E) 101
Show more

Simplifying the inequality, we have:

a^2 < 1600

a < 40

Or

-a < 40

a > -40

So we have:

-40 < a < 40

So there are 79 integer values for a. This includes the 39 possible positive values for a (1 to 39, inclusive), the 39 possible negative values for a (-1 to -39, inclusive), and 0, making a total of 79.

Answer: B
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If a^2 -10 < 1590, then how many integer values can a have 21 May 2018, 18:44
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If a^2 -10 < 1590, then how many integer values can a have?

\(a^2\)-10 < 1590. , if a = 40 , then \(a^2\) = 1600.

Critical Information:
1. We should not forget to consider negative integers
2. 0 is also included in integers.

-39 < a < 39.

A can take values from: 39 negative integers (-1 to -39) , 0 , 39 positive integers (1 to 39) = 79 Integers

Ans:B
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If a^2 -10 < 1590, then how many integer values can a have 21 May 2018, 19:00
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saswata4s
If a^2 -10 < 1590, then how many integer values can a have?

(A) 78
(B) 79
(C) 80
(D) 81
(E) 101
Show more

\(a^2 -10 < 1590\)

\(a^2 < 1590 + 10\)

\(a^2 < 1600\)

a can take values from -39 to 39. because -40 < a < 40.


A can take values from: 39 negative integers (-1 to -39) , 0 , 39 positive integers (1 to 39).

No of values that a can take - 39 + 39 +1 = 79.

Ans - B
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If a^2 -10 < 1590, then how many integer values can a have 12 Apr 2019, 17:57
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Hello JeffTargetTestPrep

Just one question,

Why is not like the following?

\(a^2 -10 < 1590\)

\(a^2 < 1600\)

\(a < (+/-) 40\) so... \(a < 40\) and \(a < - 40\)

Kind regards!
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If a^2 -10 < 1590, then how many integer values can a have 30 Apr 2021, 19:24
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\(a^2-10<1590\)
\(a^2<1600\)
-40<a<40

Then a can take the values of all the integers from -39 to +39 ->79 (don't forget to include 0).

Answer is B
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If a^2 -10 < 1590, then how many integer values can a have 03 Oct 2024, 05:41
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Always check the value for 0

Here, a^2 - 10 < 1590

a^2 < 1600

Therefore, a < | 40 |

Therefore -40 < a < 40

-1 to -39 is 39 integers, 1 to 39 is 39 integers and a can also be 0

Ans B
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