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Re: If a^2 -10 < 1590, then how many integer values can a have
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21 May 2018, 16:39
saswata4s wrote:
If a^2 -10 < 1590, then how many integer values can a have?
(A) 78 (B) 79 (C) 80 (D) 81 (E) 101
Simplifying the inequality, we have:
a^2 < 1600
a < 40
Or
-a < 40
a > -40
So we have:
-40 < a < 40
So there are 79 integer values for a. This includes the 39 possible positive values for a (1 to 39, inclusive), the 39 possible negative values for a (-1 to -39, inclusive), and 0, making a total of 79.