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If a^2 -10 < 1590, then how many integer values can a have

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If a^2 -10 < 1590, then how many integer values can a have  [#permalink]

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New post 04 Apr 2017, 04:48
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If a^2 -10 < 1590, then how many integer values can a have?

(A) 78
(B) 79
(C) 80
(D) 81
(E) 101

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Re: If a^2 -10 < 1590, then how many integer values can a have  [#permalink]

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New post 04 Apr 2017, 04:52
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Re: If a^2 -10 < 1590, then how many integer values can a have  [#permalink]

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New post 21 May 2018, 16:39
saswata4s wrote:
If a^2 -10 < 1590, then how many integer values can a have?

(A) 78
(B) 79
(C) 80
(D) 81
(E) 101


Simplifying the inequality, we have:

a^2 < 1600

a < 40

Or

-a < 40

a > -40

So we have:

-40 < a < 40

So there are 79 integer values for a. This includes the 39 possible positive values for a (1 to 39, inclusive), the 39 possible negative values for a (-1 to -39, inclusive), and 0, making a total of 79.

Answer: B
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Re: If a^2 -10 < 1590, then how many integer values can a have  [#permalink]

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New post 21 May 2018, 18:44
If a^2 -10 < 1590, then how many integer values can a have?

\(a^2\)-10 < 1590. , if a = 40 , then \(a^2\) = 1600.

Critical Information:
1. We should not forget to consider negative integers
2. 0 is also included in integers.

-39 < a < 39.

A can take values from: 39 negative integers (-1 to -39) , 0 , 39 positive integers (1 to 39) = 79 Integers

Ans:B
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Re: If a^2 -10 < 1590, then how many integer values can a have  [#permalink]

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New post 21 May 2018, 19:00
saswata4s wrote:
If a^2 -10 < 1590, then how many integer values can a have?

(A) 78
(B) 79
(C) 80
(D) 81
(E) 101


\(a^2 -10 < 1590\)

\(a^2 < 1590 + 10\)

\(a^2 < 1600\)

a can take values from -39 to 39. because -40 < a < 40.


A can take values from: 39 negative integers (-1 to -39) , 0 , 39 positive integers (1 to 39).

No of values that a can take - 39 + 39 +1 = 79.

Ans - B
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Re: If a^2 -10 < 1590, then how many integer values can a have  [#permalink]

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New post 12 Apr 2019, 17:57
Hello JeffTargetTestPrep

Just one question,

Why is not like the following?

\(a^2 -10 < 1590\)

\(a^2 < 1600\)

\(a < (+/-) 40\) so... \(a < 40\) and \(a < - 40\)

Kind regards!
GMAT Club Bot
Re: If a^2 -10 < 1590, then how many integer values can a have   [#permalink] 12 Apr 2019, 17:57
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