G(x) is the greatest integer less than or equal to x and L(x) is the l

Question

G(x) is the greatest integer less than or equal to x and L(x) is the least integer greater than or equal to x. When x is not an integer, which of the following is the value of L(x)-G(x)?

A. -2 
B. -1 
C. 0 
D. 1 
E. 2

shashankism · Answer

For this take an example.. First read the question carefully, whether x is an integer or not..
Here x is non-integer
Lets say x =1.5
so G(x) = 1
L(x) = 2

So L(x) - G(x) = 2-1 =1

Answer D

MathRevolution · Answer

==> You get G(x)=round down and L(X)=round up. Then, x≠integer, so if you substitute x=1.2, you get L(1.2)-G(1.2)=2-1=1.

The answer is D. 
Answer: D

MvArrow · Answer

Isn't zero an integer?
If x=0.5 we would have:

0 = Lx
0.5
1 = Gx

So Lx (0) - Gx (1) = -1

Am I wrong?

saurabhsavant · Answer

Hi, i guess u mixed them up G(x) = greatest integer less than or equal to x would mean that 1st integer which comes just "before" x, therefore if x = 0.5 then G(x) = 0 L(x) = least integer greater than or equal to x, would mean that 1 st integer which comes just after x, therefore if x = 0.5 them l(x) = 1 l(x)-g(x) = 1-0=1 hope it helps...

...FYI..i got the answer wrong too..

hdwnkr · Answer

Take two examples

x = 0.3(3)
L(x) = 1
G (x) = 0
Lx - Gx = 1

x= -0.3(3)
Lx = 0
Gx = 1
Lx - Gx = 0 - (-1) = 0+1 = 1

Answer is 1

pushpitkc · Answer

Given data :
G(x) is the greatest integer less than or equal to x 
L(x) is the least integer greater than or equal to x
x - Not an integer

Find L(x)-G(x)

By assuming numbers, Let x = 0.7
Now 
L(x) = 1(since 1 is the least integer greater than/equal to x)
G(x) = 0(since 1 is the greatest integer less than/equal to x)

L(x) - G(x) will always be equal to 1( Option D )

bumpbot · Answer

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G(x) is the greatest integer less than or equal to x and L(x) is the l

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G(x) is the greatest integer less than or equal to x and L(x) is the l

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