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Bunuel
Two cars start at the same point and travel in opposite directions. If one car travels at 45 miles per hour and the other at 60 miles per hour, how much time will pass before they are 210 miles apart?

(A) 0.5 hours
(B) 1 hour
(C) 1.5 hours
(D) 2 hours
(E) 2.5 hours

When cars travel in opposite directions, whether away from or toward one another, add their respective rates.

45 + 60 = 105 mph

rate * time = distance --->

D/r = t

Distance is 210 miles.

210 miles / 105 mph = 2 hours
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Leo8

{1} Find the relative speed between two cars and find the time taken: \(\frac{210}{ relative speed : 45+60}\) = \(\frac{210}{105}\) = 2 hours

Though frequently used and technically accurate, just want to note that "relative speed" can be confusing in the context of cars moving in opposite directions (whether coming toward each other or moving away from one another). In the latter scenario, "relative" also means "combined speeds where rates are added."

(IMO "relative" makes more intuitive sense when you think of the "chase," where cars are moving in the same direction and slower rate is subtracted from faster rate.)

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Leo8

{1} Find the relative speed between two cars and find the time taken: \(\frac{210}{ relative speed : 45+60}\) = \(\frac{210}{105}\) = 2 hours

Though frequently used and technically accurate, just want to note that "relative speed" can be confusing in the context of cars moving in opposite directions (whether coming toward each other or moving away from one another). In the latter scenario, "relative" also means "combined speeds where rates are added."

(IMO "relative" makes more intuitive sense when you think of the "chase," where cars are moving in the same direction and slower rate is subtracted from faster rate.)

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Kudos me if you like the approach. It will give me encouragement :)
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genxer123
By relative speed, I meant effective speed.
I would say both Car 1 and Car 2 were spreading apart with a rate of 105 miles per hour. This speed is not the exact speed of car 1 or car 2 but the effective speed at which they are moving apart. I don't see any confusion in calling this as relative speed.

you could have a chase scenario , a crash scenario - in both the cases , it is recommended to calculate the relative speed / effective speed of the whole action.

and Thanks for the Kudos :P
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Bunuel
Two cars start at the same point and travel in opposite directions. If one car travels at 45 miles per hour and the other at 60 miles per hour, how much time will pass before they are 210 miles apart?

(A) 0.5 hours
(B) 1 hour
(C) 1.5 hours
(D) 2 hours
(E) 2.5 hours

Relative speed of both cars = 45+60 = 105 miles per hour
Distance = 210 miles
Time = 210/105 = 2 hours

Answer D
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Bunuel
Two cars start at the same point and travel in opposite directions. If one car travels at 45 miles per hour and the other at 60 miles per hour, how much time will pass before they are 210 miles apart?

(A) 0.5 hours
(B) 1 hour
(C) 1.5 hours
(D) 2 hours
(E) 2.5 hours

Since we have a diverging rate problem, we can use the following formula:

distance of car 1 + distance of car 2 = 210

We can let t = the time traveled by either car, and thus the distance of car 1 is 45t and the distance of car 2 is 60t. Thus:

45t + 60t = 210

105t = 210

t = 2 hours

Answer: D
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Two cars start at the same point and travel in opposite directions. If one car travels at 45 miles per hour and the other at 60 miles per hour, how much time will pass before they are 210 miles apart?

(A) 0.5 hours
(B) 1 hour
(C) 1.5 hours
(D) 2 hours
(E) 2.5 hours

t = distance btw them / speed a + speed b
so
210 / 105 = 2
formula is based on relative speed as they are going in opp direction so both speed need to be added
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