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==> You get \(1,000(1+0.05)^2-1,000=102.5.\)

The answer is D.
Answer: D
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MathRevolution
For an investment, you start off with $1,000, the interest rate of 5%, and you deposited two years as compound interest. What is the total interest earned in 2 years?

A. $96.5
B. $98.5
C. $100.5
D. $102.5
E. $105.2

After year 1, the amount of interest earned is 0.05 x 1000 = 50 dollars, so the amount of the investment at the end of year 1 is 1,050 dollars.

The amount of interest earned in year 2 is 1,050 x 0.05 = 52.50 dollars.

Thus, the total amount of interest earned is 50 + 52.50 = 102.50 dollars.

Alternate solution:

Recall that the compound interest formula, if the interest is compounded annually, is:

A = P(1 + r)^t, where P is the principal (i.e., amount deposited), r is the interest rate, t is the number of years, and A is the total amount after the interest has been added.

So, here we have:

A = 1000(1 + 0.05)^2 = 1000(1.05)^2 = 1000(1.1025) = $1102.5. Thus, the interest earned in 2 years is:

1102.5 - 1000 = $102.5

Answer: D
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Using simple interest, the interest would be $50 for one year, or $100 for 2 years.
But since this is compound interest, the interest would have to be slightly higher, so D seems the best choice, without going into compound interest calculations.
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At end of first year interest will be 5% of 1000 = 1000*5/100= 50.
Now amount is 1000+50= 1050.

At end of second year, interest will be 5% of 1050= 1050*5/100= 52.5

Total interest = 50 + 52.5 = 102.5

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