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66% (01:57) correct
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Brent and Alexa are freelance authors. Between them, they have been published p times, with Alexa having been published n times more than Brent has. Which of the following represents the number of times that Alexa has been published?
A. (p+n)/2
B. (p−n)/2
C. p−n
D. p−2n
E. (p+2n)/2
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A. (p+n)/2
B. (p−n)/2
C. p−n
D. p−2n
E. (p+2n)/2
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Alexa = A times
Brent = B times
\(A+B = P\)
\(B=A-n\)
\(A+A-n = p\)
\(2A=p+n\)
\(A=(p+n)/2\)
Option A
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Bunuel
Solution
- • As per the given conditions
- o \(A + B = p\) ……………..(i)
o \(A = n + B\)
- o \(A – B = n\) ………..(ii)
• Adding equation (i) and (ii), we get
- o \(2A = p + n\)
o \(A = \frac{(p+n)}{2}\)
• Thus, the correct answer is Option A.
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Bunuel
Or just plug in values. Say they both have been published 10 times (p = 10) and Alexa has been published 10 times more i.e. Brent has been published 0 times.
We need the option that gives 10 when p = n = 10
Only (A) does that.
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Expert reply
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Bunuel
Let A and B denote the number of times Alexa and Brent has been published, respectively.
Since they have been published p times,
A + B = p.
Since the number of publications of Alexa is n more than Brent,
A = B + n.
Let’s write the second equality as
B = A - n.
Let’s substitute this expression for B in the first equation:
A + (A - n) = p
2A = p + n
A = (p + n)/2
Answer: A
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A+B----------p times
B-------------b times
Case - 1: Alexa having been published n times more than Brent has.
A-------------nb times (n times more than Brent!!!)
p = b + nb
nb = p-n | C
Case - 2: Alexa having been published n more times than Brent has.
A-------------n+b times (n more times than Brent!!!)
p = b + n + b
2b = p-n
b = [(p-n)/2] | A
Bunuel, Vyshak, Engr2012, mikemcgarry, Abhishek009, VeritasPrepKarishma, Skywalker18, msk0657, abhimahna
I got this question wrong because i followed case-1, am i miss-understanding something?
Please clarify.
Thanks
B-------------b times
Case - 1: Alexa having been published n times more than Brent has.
A-------------nb times (n times more than Brent!!!)
p = b + nb
nb = p-n | C
Case - 2: Alexa having been published n more times than Brent has.
A-------------n+b times (n more times than Brent!!!)
p = b + n + b
2b = p-n
b = [(p-n)/2] | A
Bunuel, Vyshak, Engr2012, mikemcgarry, Abhishek009, VeritasPrepKarishma, Skywalker18, msk0657, abhimahna
I got this question wrong because i followed case-1, am i miss-understanding something?
Please clarify.
Thanks
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Bunuel
manishtank1988
Hi manishtank1988 ,
Between them, they have been published p times, with Alexa having been published n times more than Brent has .
A = b+n (since Alexa having been published n times more than Brent has -- we add here )
If question was that Alexa was published n times the number of times Brent was published, then A = b*n is correct
B = b
2b+n = p
=> b = (p-n)/2
A = (p-n)/2 +n = (p+n)/2
Answer A
Hope this helps!!
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Let A be the times Alexa has been published and let B be the times Brent has been published.
They have been published p times i.e. A+B = p
Now, Alexa has been published n times more than Brent. --> A= B+n --> B = A - n
Substituting value of B in original equation.
A+A-n = p --> 2A = p+n --> A=(p+n)/2
Answer A.
Sent from my SM-N9007 using GMAT Club Forum mobile app
They have been published p times i.e. A+B = p
Now, Alexa has been published n times more than Brent. --> A= B+n --> B = A - n
Substituting value of B in original equation.
A+A-n = p --> 2A = p+n --> A=(p+n)/2
Answer A.
Sent from my SM-N9007 using GMAT Club Forum mobile app
Posts: 112
EgmatQuantExpert
I got this question wrong because I chose "p-n/2." I substituted A (B+n) into B+A=p. I don't understand why we have to switch A=B+n to B=A-n....someone please clarify this for me. Thanks!
rnz
If you substitute A = n + B into A + B = p, you get: (n + B) + B = p --> 2B = p - n --> B = (p - n)/2. Yes, but you are answering WRONG question. The question asks: Which of the following represents the number of times that Alexa has been published? You found the number of times that Brent has been published: B = (p - n)/2.
Hope it's clear.
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