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05 Oct 2017, 01:41
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Difficulty:
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Question Stats:
79% (01:38) correct
21%
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wrong
based on 41
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If polygon ABCDE above has perimeter 26 and equilateral triangle BCD has perimeter 18, what is the area of the rectangular region ABDE?
(A) 6
(B) 12
(C) 24
(D) 32
(E) 48
Attachment:
2017-10-04_1125_003.png [ 6.48 KiB | Viewed 5102 times ]
05 Oct 2017, 02:09
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Perimeter of polygon ABCDE = 26
Perimeter of equilateral triangle BCD = 18, so each side of triangle be of length 6
So BD=AC=6
subtracting AE, BC, CD from the perimeter of polygon ABCDE, we get AB + ED = 8, so AB=ED=4
Now the rectangle ABDE had length =6 and breadth = 4, so area of triangle ABDE = 6*4=24
Perimeter of equilateral triangle BCD = 18, so each side of triangle be of length 6
So BD=AC=6
subtracting AE, BC, CD from the perimeter of polygon ABCDE, we get AB + ED = 8, so AB=ED=4
Now the rectangle ABDE had length =6 and breadth = 4, so area of triangle ABDE = 6*4=24
raki99
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05 Oct 2017, 04:10
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This approach may help you......................
Perimeter of polygon ABCDE = 26
Perimeter of equilateral triangle BCD = 18, so each side of triangle be of length 6
So BD=AC=6
subtracting AE, BC, CD from the perimeter of polygon ABCDE, we get AB + ED = 8, so AB=ED=4
Now the rectangle ABDE had length =6 and breadth = 4, so area of triangle ABDE = 6*4=24
Perimeter of polygon ABCDE = 26
Perimeter of equilateral triangle BCD = 18, so each side of triangle be of length 6
So BD=AC=6
subtracting AE, BC, CD from the perimeter of polygon ABCDE, we get AB + ED = 8, so AB=ED=4
Now the rectangle ABDE had length =6 and breadth = 4, so area of triangle ABDE = 6*4=24
