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02 Nov 2017, 23:08
Kudos
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
69% (01:53) correct
31%
(01:57)
wrong
based on 228
sessions
History
Date
Time
Result
Not Attempted Yet
How many squares with sides 1/2 inch long are needed to cover a rectangle that is 6 feet long and 4 feet wide? (1 foot = 12 inches)
(A) 24
(B) 96
(C) 3,456
(D) 13,824
(E) 14,266
(A) 24
(B) 96
(C) 3,456
(D) 13,824
(E) 14,266
03 Nov 2017, 00:15
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Bunuel
The first step is to convert the rectangle to inches.
Since the rectangle is 4 ft by 6 ft, the dimensions of the rectangle will be 48 inch by 72 inch.
We have been asked to find out how many square of side 0.5 inch are needed to cover this rectangle.
The area covered by the rectangle is 48*72 inch and we will be needing x squares to cover this rectangle.
\(0.5*0.5*x = 48*72\)
\(x = \frac{48}{0.5} * \frac{72}{0.5} = 96 * 144 = 13824\)(Option D)
04 Nov 2017, 01:36
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Bunuel
Hi Bunuel,
As per my understanding, length is always greater than width.
Is it OK to say length is 4ft and width is 6ft? This implies that width is greater than length.
