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Sangeeta2018
Joined: 11 Jul 2016
Last visit: 20 Jun 2018
Posts: 40
Own Kudos:
Given Kudos: 70
Location: India
Concentration: Technology, General Management
Schools: Schulich Sept 18 Intake (A)
GMAT 1: 550 Q36 V30
GPA: 3.65
WE:Information Technology (Consulting)
15 Nov 2017, 22:06
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
79% (01:21) correct
21%
(02:05)
wrong
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The highest term in a set is 3SD above the Mean. The lowest term is 4SD below the mean. If the highest term is 200 and Range is 140, find the Standard Deviation.
A. 20
B. 60
C. 140
D. 200
E. 300
Source: Experts' Global
A. 20
B. 60
C. 140
D. 200
E. 300
Source: Experts' Global
15 Nov 2017, 23:03
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Sangeeta2018
The highest term in a set is 3SD above the Mean: Highest term = Mean +3SD ;
The lowest term is 4SD below the mean: Lowest term = Mean - 4SD;
Subtract 2 from 1:
Highest term - Lowest term = (Mean +3SD) - (Mean - 4SD);
Range = 7SD;
140 = 7SD;
SD = 20.
Answer: A.
15 Nov 2017, 23:09
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Sangeeta2018
Let mean be denoted as M
Highest term = M + 4SD
Lowest term = M - 3SD
Range = 140, i.e.
M + 4sd - M + 3sd = 140
7sd = 140
sd = 20;
or
M+4sd = 200 .. eq 1
Range = 140 --> 200 - Least number = 140 ==> least number = 60
M - 3sd = 60 .. eq 2
Solve for sd from eq 1 and 2; you will get 7sd = 140 and sd = 20;
Now my doubt is - where is 20 in the answer choices ??? or did I make a mistake
