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Difficulty:
5%
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Question Stats:
91% (00:59) correct
9%
(01:20)
wrong
based on 139
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Which of the following could be the sum of three consecutive integers?
(A) 29
(B) 46
(C) 57
(D) 92
(E) 100
_________________
(A) 29
(B) 46
(C) 57
(D) 92
(E) 100
_________________
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Bunuel
Let the three consecutive integers be x-1, x, x+1
the sum of three consecutive integers = x-1+x+x+1=3n
Here ans should be multiple of 3
Hence C
Posts: 1,001
Bunuel
As we can easily create an expression, we'll jsut do it.
This is a Precise approach.
Writing our 3 integers as n, n+1 and n+2, their sum is 3n+3.
So our answer must be divisible by 3.
To test if our numbers are divisble by 3, we'll see if their digits sum to 3.
A. 2 + 9 = 11. Not divisible by 3.
B. 4 + 6 = 10. Not divisible by 3.
C. 5 + 7 = 12. Divisible by 3!
(C) is our answer.
Abhishek009
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Posts: 5,878
Bunuel
Sum of three consecutive Integers will be
x + ( x + 1 ) + ( x + 2) = 3x + 3
Result will be Odd when x = Even &
Result will be Even when x = Odd
Check the options,
(A) If 3x + 3 = 29 ( Not Possible )
(B) If 3x +3 = 46 ( Not Possible )
(C) If 3x +3 = 57 ( Possible x = 18 )
That's our answer (C)
_________________
Posts: 14
Let three consecutive numbers are X, X+1 , and X+2.
Their sum =X+ X+1 + X+2
= 3x+3
=3 (X+1)
Therefore, sum of three consecutive numbers is multiple of 3.
Therefore,option C, 57 is the answer.
Posted from my mobile device
Their sum =X+ X+1 + X+2
= 3x+3
=3 (X+1)
Therefore, sum of three consecutive numbers is multiple of 3.
Therefore,option C, 57 is the answer.
Posted from my mobile device
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