Bunuel wrote:

Which of the following could be the sum of three consecutive integers?

(A) 29

(B) 46

(C) 57

(D) 92

(E) 100

As we can easily create an expression, we'll jsut do it.

This is a Precise approach.

Writing our 3 integers as n, n+1 and n+2, their sum is 3n+3.

So our answer must be divisible by 3.

To test if our numbers are divisble by 3, we'll see if their digits sum to 3.

A. 2 + 9 = 11. Not divisible by 3.

B. 4 + 6 = 10. Not divisible by 3.

C. 5 + 7 = 12. Divisible by 3!

(C) is our answer.

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