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Bunuel
For the infinite sequence \(a_1\), \(a_2\), ..., \(a_n\), the value of \(a_n\) is the sum of all previous terms in the sequence from \(a_1\) through \(a_{n−1}\), inclusive. If \(a_n=x\) and \(n>2\), which of the following expresses \(a_{n+2}\) in terms of x?

A. x+2

B. 2x

C. 3x

D. 4x

E. 8X

\(a_n\) is the sum of all elements from \(a_1\) to \(a_{n-1}\)

Lets say sum of all elements from \(a_1\) to \(a_{n-1}\) = x = \(a_1\)

\(a_{n+1}\) is a sum of \(a_1\) and all elements from \(a_1\) to \(a_{n-1}\) = x + x = 2x

\(a_{n+2}\) is a sum of \(a_{n+1}\) and all elements from \(a_1\) to \(a_{n}\) = 2x+2x = 4x


Option D
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PLUG-IN- a, b=1,1 n see the pattern.
Hence 4 is the ans.
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