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MvArrow
Bunuel can you kindly explain to me what happens to the ratios when, for example in this problem, they "double"?

In club B we have Single/Married = 3/2, if the ratio of single women to married women in club B is twice that of club A what the original ratio becomes?

(Men:Women) in A = 1/1

(Men:Women) in B is twice that of A, so in B it's = 2*(1/1) = 2/1.
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Bunuel
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Bunuel can you kindly explain to me what happens to the ratios when, for example in this problem, they "double"?

In club B we have Single/Married = 3/2, if the ratio of single women to married women in club B is twice that of club A what the original ratio becomes?

(Men:Women) in A = 1/1

(Men:Women) in B is twice that of A, so in B it's = 2*(1/1) = 2/1.

3. Fractions, Decimals, Ratios and Proportions



For more:
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Hope it helps.
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Bunuel
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MvArrow
Bunuel can you kindly explain to me what happens to the ratios when, for example in this problem, they "double"?

In club B we have Single/Married = 3/2, if the ratio of single women to married women in club B is twice that of club A what the original ratio becomes?

(Men:Women) in A = 1/1

(Men:Women) in B is twice that of A, so in B it's = 2*(1/1) = 2/1.

3. Fractions, Decimals, Ratios and Proportions



For more:
ALL YOU NEED FOR QUANT ! ! !
Ultimate GMAT Quantitative Megathread


Hope it helps.

Thanks A LOT :-)
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Club B:

Total Members in B = 840
Ratio of men to women = 2 : 1
Men = 560 and Women = 280

Total Women in B = 280
Ratio of single women to married women = 3 : 2
Single women = 168 and Married women = 112

Club A:

Total members in A = Total members in B = 840
(Men : Women) in B = 2(Men : Women) in A
(Men : Women) in A = 1 : 1
Men in A = 420; Women in A = 420

(Single women : Married women) in B = 2(Single women: Married women) in A
(Single women : Married women) in A = 3 : 4
Single women in A = 180; Married women in A = 240

Total married women = 112 + 240 = 352

Answer: B
Hi, how did you get the twice ratio? can you share the logic please?
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