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Bunuel
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Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
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Apply average formula:

\(\frac{x+y+30}{3}\)= 10

x+y+30= 30

x+y=0.........No need to bother calculate as it is always ZERO

Answer: A
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Bunuel
If the average of x, y, and 30 is 10, then the average of x and y is

(A) 0

(B) 5

(C) 15/2

(D) 10

(E) 30
IMO A x+y+30= 10*3= 30
then X+Y=0 and their average is X+Y/2=0/2 =0
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Bunuel
If the average of x, y, and 30 is 10, then the average of x and y is

(A) 0

(B) 5

(C) 15/2

(D) 10

(E) 30


x+y+30/3 = 10

x+y+30 = 30

x+y = 0

avg = 0

(A) imo
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Bunuel
If the average of x, y, and 30 is 10, then the average of x and y is

(A) 0

(B) 5

(C) 15/2

(D) 10

(E) 30

Since the average of x, y, and 30 is 10, we have:

(x + y + 30)/3 = 10

x + y + 30 = 30

x + y = 0

So the average of x and y is (x + y)/2 = 0/2 = 0.

Answer: A
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