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22 Feb 2018, 20:51
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
77% (01:24) correct
23%
(01:54)
wrong
based on 66
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A magician wants to ship a magic wand to the location of his next show. The rectangular box he has available for this purpose measures 6 inches wide by 8 inches long by 10 inches high. What is the longest cylindrical wand of negligible diameter that can be shipped in this box?
(A) 10 inches
(B) \(8\sqrt{2}\) inches
(C) \(8\sqrt{3}\) inches
(D) \(10\sqrt{2}\) inches
(E) \(10\sqrt{3}\) inches
(A) 10 inches
(B) \(8\sqrt{2}\) inches
(C) \(8\sqrt{3}\) inches
(D) \(10\sqrt{2}\) inches
(E) \(10\sqrt{3}\) inches
22 Feb 2018, 22:04
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Bunuel
The box in which the magician wants to shift his magic wand is a cuboid.
The maximum height of the magic wand that can be shipped in the box is
the distance of the diagonal.
The diagonal can be calculated using the formulae \(\sqrt{Length^2 + Breadth^2 + Height^2} = \sqrt{36 + 64 + 100} = \sqrt{200} = 10\sqrt{2}\)
Therefore, the longest cylindrical wand of negligible diameter will be \(10\sqrt{2}\) (Option D)
22 Feb 2018, 22:22
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We can find the solution using the diagonal of a rectangle formula -\(\sqrt{36+64+100}\) = \(\sqrt{200}\) = 10\(\sqrt{2}\)
Ans: 10\(\sqrt{2}\)
Ans: 10\(\sqrt{2}\)
