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Bunuel
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Bunuel
At a bakery, chocolate chip cookies sell for $2.00 and oatmeal raisin cookies sell for $1.00. If Paul buys 18 chocolate chip cookies and 12 oatmeal raisin cookies, what is the average price he pays per cookie?

A. $1.20
B. $1.40
C. $1.50
D. $1.60
E. $2.00

\(\frac{2*18 + 1*12}{18 + 12}\)

= \(1.60\), Answer will be (D)
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pushpitkc
Bunuel
At a bakery, chocolate chip cookies sell for $2.00 and oatmeal raisin cookies sell for $1.00. If Paul buys 18 chocolate chip cookies and 12 oatmeal raisin cookies, what is the average price he pays per cookie?

A. $1.20
B. $1.40
C. $1.50
D. $1.60
E. $2.00

Since the proportion of chocolate chip cookies to oatmeal raisin cookies is 3:2,
we can calculate the average price for a cookie to be \(\frac{3*2 + 2*1.5}{5} = \frac{5 + 3}{5} = $1.6\)(Option D)

P.S This concept of bringing down the numbers to proportions can be really useful
when the numbers are bigger!

take the weighted average of the two prices to find the average price of cookie!

Nice solution. +1 Kudos to you sir.
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Bunuel
At a bakery, chocolate chip cookies sell for $2.00 and oatmeal raisin cookies sell for $1.00. If Paul buys 18 chocolate chip cookies and 12 oatmeal raisin cookies, what is the average price he pays per cookie?

A. $1.20
B. $1.40
C. $1.50
D. $1.60
E. $2.00

We can create the following equation:

[2(18) + 12]/30 = 48/30 = 8/5 = 1.60

Answer: D
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