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Bunuel
A number of students from the same high school graduating class are enrolled at the same regional university in the fall semester. Of these students, 52 are enrolled in a mathematics course, 52 are enrolled in a psychology course, and 64 are enrolled in an English course. None of the students are enrolled in both mathematics and psychology. If 12 of the students are enrolled in both mathematics and English and 22 are enrolled in both psychology and English, how many of the students are in at least one of these three courses?

(A) 104
(B) 134
(C) 142
(D) 146
(E) 158

I like to solve 3-overlapping sets problems with a diagram as it helps me visualize the data better.

Please find the image with solution.

Best,
Gladi
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Bunuel
A number of students from the same high school graduating class are enrolled at the same regional university in the fall semester. Of these students, 52 are enrolled in a mathematics course, 52 are enrolled in a psychology course, and 64 are enrolled in an English course. None of the students are enrolled in both mathematics and psychology. If 12 of the students are enrolled in both mathematics and English and 22 are enrolled in both psychology and English, how many of the students are in at least one of these three courses?

(A) 104
(B) 134
(C) 142
(D) 146
(E) 158

We can use the following equation:

#(at least one course) = #(M) + #(P) + #(E) - #(M & P) - #(M & E) - #(P & E) + #(M & P & E)

Since there are no students enrolled in both Mathematics and Psychology, #(M & P) = 0 and #(M & P & E)
= 0 and we have:

#(at least one course) = 52 + 52 + 64 - 0 - 12 - 22 + 0

#(at least one course) = 134

Answer: B
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I found B as answer.

considering number of student who enrolled for all 3 subject is zero and number of students enrolled for Mathematics & Psychology is zero (Given)
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