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kunalcvrce
3 defective
12 total
9 non defective


neither of first two defective = 9/12 x 9/12(since not replaced) = 9/16



„Not replaced“ means that in the second choice you only have 11 left to choose from, doesn’t it?

Hence -> 6/11
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kunalcvrce
3 defective
12 total
9 non defective


neither of first two defective = 9/12 x 9/12(since not replaced) = 9/16

your answer is for replaced

not please solve not replaced

9/12 now 1 ball is removed

8/11

this becomes the new fraction 6/11 would be the answer IMO
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JaBre
kunalcvrce
3 defective
12 total
9 non defective


neither of first two defective = 9/12 x 9/12(since not replaced) = 9/16



„Not replaced“ means that in the second choice you only have 11 left to choose from, doesn’t it?

Hence -> 6/11

Correct my mistake..Thanks
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Bunuel
Three of 12 remote controls in a box are defective. The remote controls are tested one at a time and not replaced in the box after testing. What is the probability that neither of the first two remote controls tested is defective?

(A) 1/6
(B) 2/9
(C) 6/11
(D) 9/16
(E) 3/4

Since there are 9 non-defective remotes out of 12 in the box, the probability that the first remote selected is not defective is 9/12, or 3/4. We don’t put the first selected remote control back in the box. Thus, there are now 11 remotes in the box, and 8 of them are not defective. Thus, the probability that the second remote control is not defective is 8/11.

Thus, the probability that the first two remote controls are not defective is 9/12 x 8/11 = 3/4 x 8/11 = 24/44 = 6/11.

Answer: C
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JaBre
kunalcvrce
3 defective
12 total
9 non defective


neither of first two defective = 9/12 x 9/12(since not replaced) = 9/16



„Not replaced“ means that in the second choice you only have 11 left to choose from, doesn’t it?

Hence -> 6/11


:thumbsup:

Also, can't we do similar questions by simply using 9C2/12C2
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