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13 Apr 2018, 03:36
Kudos
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
84% (01:26) correct
16%
(01:24)
wrong
based on 80
sessions
History
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Time
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Not Attempted Yet
In driving a round trip from City A to City B, a motorist drives to City B and, on the way back to City A, by the same route, stops at a service station at a location that is 10 percent of the distance to City A from City B. When the motorist stops at the service station, what percent of the round trip is completed?
(A) 40%
(B) 45%
(C) 55%
(D) 60%
(E) 65%
(A) 40%
(B) 45%
(C) 55%
(D) 60%
(E) 65%
Updated on: 13 Apr 2018, 06:35
Originally posted by houston1980 on 13 Apr 2018, 03:43.
Last edited by houston1980 on 13 Apr 2018, 06:35, edited 1 time in total.
Last edited by houston1980 on 13 Apr 2018, 06:35, edited 1 time in total.
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Bunuel
City A to B is 50% of the total journey.
City B to A is 50% of the total journey.
10% of City B to A is 10%*(50%) = 5%
Percent of round trip completed is therefore 50% + 5% = 55%
Hence option C = 55% is the answer.
Give me +1 Kudos if you like the explanation. Thanks.
13 Apr 2018, 04:20
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Let the distance between A & B be x, so total distance to be covered = 2x.
Now, the stop takes places at a location that is 10 percent of the distance to City A from City B = 0.1x
Hence the percent of the round trip is completed = (x+0.1x) / 2x *100 = 1.1x/2x *100 = 5.5*100 = 55%
Now, the stop takes places at a location that is 10 percent of the distance to City A from City B = 0.1x
Hence the percent of the round trip is completed = (x+0.1x) / 2x *100 = 1.1x/2x *100 = 5.5*100 = 55%
