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17 Apr 2018, 05:12
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
86% (01:44) correct
14%
(02:12)
wrong
based on 287
sessions
History
Date
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Julia and Keaton are hiking on the same trail. Julia hikes at a rate of 3 miles per hour and starts hiking at 9:00 AM. If Keaton leaves at 9:30 and catches up with Julia at 12:30 PM, at what rate has Keaton been hiking, in miles per hour?
A. 1.5
B. 2.5
C. 3.5
D. 3.75
E. 4.0
A. 1.5
B. 2.5
C. 3.5
D. 3.75
E. 4.0
17 Apr 2018, 05:24
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Bunuel
Distance is same for both Julia and Keaton.
Julia distance = 3*3.5 = 14 miles
Keaton speed = distance/time = 14/3 = 3.5 miles per hour
Hence option C = 3.5 is the answer.
17 Apr 2018, 06:15
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Bunuel
Julia starts hiking at \(9\) and 'ends' at \(12.5\). Thus, total time for Julia is \(12.5 - 9 = 3.5\)
\(Distance = Rate*Time = 3*3.5 = 10.5\)
Keaton starts hiking at \(9.5\) and 'ends' at \(12.5\). Thus, total time for Keaton is \(12.5 - 9.5 = 3\)
\(Distance = Rate*Time\). => \(10.5 = x*3\) => \(x = 3.5\)
Answer: C
