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Bunuel
The units digit of a 3-digit number is 1/3 times the hundreds digit and twice the tens digit. What is the number?

(A) 126
(B) 216
(C) 312
(D) 612
(E) 621

u=h/3
u=2t
h/3=2t
h=6t
t has to be 1
h=6
u=2
612
D
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Bunuel
The units digit of a 3-digit number is 1/3 times the hundreds digit and twice the tens digit. What is the number?

(A) 126
(B) 216
(C) 312
(D) 612
(E) 621

Scanning answer choices is the best approach here.

Units digit is 1/3 of the hundreds digit. Only D fits.

Answer: D
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Bunuel
The units digit of a 3-digit number is 1/3 times the hundreds digit and twice the tens digit. What is the number?

(A) 126
(B) 216
(C) 312
(D) 612
(E) 621

Since the units digit is 1/3 the hundreds digit, the hundreds digit is either 9, 6 or 3, and in that case the units digit could be 3, 2, or 1, respectively.

Since the units digit is twice the tens digit, the only possible option for the units digit is 2, so the tens digit is 1 and the hundreds digit is 6, so we have 612 as the number.

Alternate Solution:

Let’s consider the answer choices. Since the units digit is twice the tens digit, we see that only choices C and D meet this requirement, each having a tens digit of 1 and a units digit of 2.

Checking the hundreds digit of choice C (312) and choice D (612), we see that the units digit of 612 is 1/3 its hundreds digit because 1/3 x 6 = 2.

Answer: D
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