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Bunuel
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Bunuel
If \(xy^2 = 12\) and \(xy = 4\), then x =


A. 1

B. 2

C. \(\sqrt{3}\)

D. \(\frac{2}{3}\)

E. \(\frac{4}{3}\)
\(xy^2 = 12\) and \(xy=4\)

\(x*y*y = 12\), i.e., \((x*y)*y=12\)
\(4*y=12\)
\(y=3\)

\(x=?\)
\(xy=4\), and \(y=3\)
\(x*3=4\)
\(x =\frac{4}{3}\)

Answer E
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Bunuel
If \(xy^2 = 12\) and \(xy = 4\), then x =


A. 1

B. 2

C. \(\sqrt{3}\)

D. \(\frac{2}{3}\)

E. \(\frac{4}{3}\)

Let’s first establish that both x and y must be positive. Since xy^2 = 12, we see that x must be positive. And since xy = 4, we see that y must also be positive.

Dividing the first equation by the second, we have:

y = 3

Substituting y = 3 into the second equation, we have:

x(3) = 4

x = 4/3

Alternate Solution:

Let’s rewrite the first equation as:

x(xy) = 12

We are given that xy = 9, so we can substitute:

x(9) = 12

x = 12/9 = 4/3

Answer: E
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Bunuel
If \(xy^2 = 12\) and \(xy = 4\), then x =


A. 1

B. 2

C. \(\sqrt{3}\)

D. \(\frac{2}{3}\)

E. \(\frac{4}{3}\)


1.divide:
\(xy^2 = 12\)
/\(xy = 4\)
y=3
2. substitute:
x=4/3 => E
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Bunuel
If \(xy^2 = 12\) and \(xy = 4\), then x =


A. 1

B. 2

C. \(\sqrt{3}\)

D. \(\frac{2}{3}\)

E. \(\frac{4}{3}\)

\(y = \frac{xy^2}{xy}\)

So, \(y = \frac{12}{4}\)

Or, \(y = 3\)

We know that \(xy^2 = 12\)

Or, \(9x = 12\)

Or, \(x = \frac{4}{3}\), Hence Answer must be (E)
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\(xy^2 = 12\)
\(xy*y = 12\)
\(4y = 12\)
\(y=3\)
so
\(3x=4\)
\(x=\frac{4}{3}\)
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