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Bunuel
When the number of people in an office is divided by 12, the remainder is 0. If 3/2 times the number of people in the office is divided by 12, and the remainder resulting from this operation is greater than 0, the remainder must be

A. 1
B. 2
C. 3
D. 5
E. 6

Solution:
Let People=P. Given P=12x (note, there is no remainder because 12 divides P completely.)
Question if \(\frac{3}{2}\)(P) is divided by 12 what will be the remainder?
\(\frac{3}{2}\)(P)/12= {\(\frac{3}{2}\)(12x)}/12 = \(\frac{18x}{12}\) = \(\frac{12x}{12}\)+ \(\frac{2x}{12}\) = x+\(\frac{1}{6}\)*x. The remainder is \(\frac{1}{6}\)*x, looking at the answer choices only 6 is a multiple 6.

Answer: (E).
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Bunuel
When the number of people in an office is divided by 12, the remainder is 0. If 3/2 times the number of people in the office is divided by 12, and the remainder resulting from this operation is greater than 0, the remainder must be

A. 1
B. 2
C. 3
D. 5
E. 6

Because division by 12 yields a remainder of 0, we see that the number of people in the office is a multiple of 12. We can multiply a few multiples of 12 by 3/2, and we have:

12 x 3/2 = 18 ---> 18/12 = 1 R 6

24 x 3/2 = 36 ---> 36/12 = 3 R 0

36 x 3/2 = 54 ---> 54/12 = 4 R 6

48 x 3/2 = 72 ---> 72/12 = 6 R 0

We see that when we divide those results by 12, we get a remainder of either 0 or 6. So, the only possible remainder that is greater than 0 is 6.

Answer: E
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Given that When the number of people in an office is divided by 12, the remainder is 0. And we need to find the remainder when 3/2 times the number of people in the office is divided by 12

Since the number of people is divisible by 12 (because remainder when divided by 12 is 0)
=> Number of people can be taken as 12k (Where k is an integer)

\(\frac{3}{2}\) of number of people = \(\frac{3}{2}\) * 12k = 18k

Now, 18k when divided by 12 gives a remainder greater than 0
If we take k = 1, we will get 18

18 when divided by 12 gives 6 remainder.

So, Answer will be E
Hope it helps!


Watch the following video to MASTER Remainders

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