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MathRevolution
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Dear MathRevolution,

Please check the answer options. As the GMATPrepNow above, I have got 36 h (E), but not 24(C) as you refer to. Thanks.
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=>

Suppose W is the total amount of work required to do the job and that RA and RB are the work rates of machines A and B, respectively.
Then the original condition tells us that RB = \((\frac{1}{2})\)RA.

Since machine A worked on the job for 6 hours, \(\frac{1}{4}\) of the job has been done, and \((\frac{3}{4})\)W is left.
The time T that machine B takes to complete the job is T = (3/4)W / RB = (3/4)W / (1/2)RA = (6/4)W/RA = \((\frac{6}{4})\)*24 = 36.

Therefore, the answer is E.

Answer: E
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MathRevolution
[GMAT math practice question]

Working alone at its constant rate, machine A can complete a job in 24 hours. The work rate of machine B is 1/2 that of machine A. If machine A works on the job for 6 hours and machine B completes the job, how long does it take machine B to finish the job?

A. 12hrs
B. 16hrs
C. 24hrs
D. 32hrs
E. 36hrs

Rate of A = 1/24

So, Rate of B = 1/2 * 1/24 = 1/48

Work done by A in 6 hours = 6*1/24 = 1/4

Remaining work done = 1 - 1/4 = 3/4

Time taken by B to complete the work = W/R

= 3/4 * 48/1

= 3*12

= 36 hrs

(E)
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MathRevolution
[GMAT math practice question]

Working alone at its constant rate, machine A can complete a job in 24 hours. The work rate of machine B is 1/2 that of machine A. If machine A works on the job for 6 hours and machine B completes the job, how long does it take machine B to finish the job?

A. 12hrs
B. 16hrs
C. 24hrs
D. 32hrs
E. 36hrs
A did 25% job.

75% remains for which B will take twice of 75% of 24

.75 x 24 x 2 = 36

E.

Sent from my SM-T285 using GMAT Club Forum mobile app
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MathRevolution
[GMAT math practice question]

Working alone at its constant rate, machine A can complete a job in 24 hours. The work rate of machine B is 1/2 that of machine A. If machine A works on the job for 6 hours and machine B completes the job, how long does it take machine B to finish the job?

A. 12hrs
B. 16hrs
C. 24hrs
D. 32hrs
E. 36hrs

Time required by B to complete the work is 48 Hours & Time required by A to complete the work is 24 Hours.

Let the total work be 48 Units

So, Efficiency of A is 2 Units/Hr & Efficiency of B is 1 Units/Hr

Work completed by A in 6 Hours is 2*6 = 12 Units ; Work left is 48 - 12 = 36 Units....

So, Time required to complete the remainig work by B is 36 Hours, Answer must be (E)
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Rate of B is HALF Rate of A

Means that B is Half as efficient as A

For a constant output of work, rate of work is inversely proportional to time needed to complete the work

So B will take TWICE as Long as A for any given output of work.

A takes 6 hours to complete (1/24) (6) = 6/24 = 1/4th of job

(3/4) of Job remains


If A takes 6 hours ————> to do (1/4) of job

Then B takes TWICE as long: 12 hours ———> to do (1/4) of job


But, B must complete the remaining work: the (3/4) of the job remaining

Since each (1/4) of job takes B 12 hours:


(12) + (12) + (12) = 36 hours

*E*

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