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03 May 2018, 02:28
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
70% (02:30) correct
30%
(02:38)
wrong
based on 157
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In 1999, Diana read 10 English books and 7 French books. In 2000, she reads twice as many French books as English books. If 60% of the books that she read during the two years were French, how many books did she read in 2000?
A. 16
B. 26
C. 32
D. 39
E. 48
A. 16
B. 26
C. 32
D. 39
E. 48
03 May 2018, 02:35
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60% is french of the total 100% all books.
(7+2x)/(17+3x) = .6
7+2X = 0.6(17+3X)
7+2X = 10.2 +1.8X
2x-1.8X= 10.2-7
.2x = 3.2
x = 16
oops the total books = 3x= 48
Posted from my mobile device
(7+2x)/(17+3x) = .6
7+2X = 0.6(17+3X)
7+2X = 10.2 +1.8X
2x-1.8X= 10.2-7
.2x = 3.2
x = 16
oops the total books = 3x= 48
Posted from my mobile device
04 May 2018, 14:12
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Bunuel
Priyanka8793 , belated welcome and nice solution! +1
Use answer choices
French:English books during the year 2,000 = 2x:1x
Total of ratio parts: 3x. The answer must be a multiple of 3
Eliminate A, B, C
Try D) 39 books read during year 2000
3x = 39, so x, multiplier, = 13
# of French books: 2x = 26
# of English books: x = 13
Two-year total of all books?
English: 13 + 10 = 23
French: 26 + 7 = 33
Overall: 23 + 33 = 46
French/Total should = \(\frac{3}{5}\)
\(\frac{33}{46}\). Stop. That fraction cannot equal \(\frac{3}{5}\)
If unsure, check. No need to divide.
-- estimate: \(\frac{3}{5}\) of 45 = 27 French
-- or multiply (46 * 0.6) = 27.6 French
In answer D, French = 33. Too great.
By POE, the Answer is
Check? E) 48 total books in year 2000
3x = 48, so x = 16
French in 2000: 2x = 32
English in 2000: 1x = 16
Total E: 16 + 10 = 26
Total F: 32 + 7 = 39
Overall total: (26 + 39) = 65
\(\frac{39}{65} = \frac{3}{5} = 60\) percent
That's a match.
Answer
