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option D

3x+5 = 3.3m +5 = 9m+5

9m+5 will leave a remainder when divided by 3 as only 9m is a multiple of 3 and not 5.
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i really get carried away by the "what ifs"
i solved this question using the plugging in the numbers approach
do i really have to check plugging 2-3 numbers or just plugging 1 number will always suffice
this might very stupid, but can i please get a reply.....
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