If the distances between each pair of consecutive ticks are equal, wha

Question

5.30.png If the distances between each pair of consecutive ticks are equal, what is the value of x? A. 2^{12} B. 3(2^{10}) C. 5(2^{10}) D. (2^{13}) E. 3(2^{12})

ayushthebest · Answer

B
X-2^11=2^11-2^10
X = 2^10(2+2-1)
X = 3(2^10)

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BrentGMATPrepNow · Answer

If the distances between each pair of consecutive ticks are equal, we can write:  2^11 - 2^10 = x - 2^11 
We must solve this equation for x....

Add 2^11 to both sides: 2^11 + 2^11 - 2^10 = x
Combine the two 2^11's to get: 2(2^11) - 2^10 = x
Rewrite 2 as 2^1 to get: (2^1)(2^11) - 2^10 = x
Simplify to get: 2^12 - 2^10 = x
Factor our 2^10 to get: 2^10(2^2 - 1) = x
Evaluate to get: 2^10(4 - 1) = x
Simplify to get: 2^10(3) = x

Answer: B

Cheers,
Brent

JeffTargetTestPrep · Answer

The space between each pair of consecutive ticks is 2^11 - 2^10, so x is:

2^10(2 + 2 - 1) = 2^10 x 3

Answer: B

MathRevolution · Answer

=>

The distance between each pair of consecutive ticks is  2^{11} – 2^{10} = 2*2^{10} – 2^{10} = 2^{10}. 
Thus,  x = 2^{11} + 2^{10} = 2*2^{10} + 2^{10} = 3(2^{10}) .

Therefore, the answer is B.
Answer: B

rahulkhannad · Answer

(2^{10})  = 1024,   (2^{11})  = 2048

A common mistake is to assume the next value is   (2^{12})  (4096). However, the problem states that the distances between pairs are equal. This means the correct answer is 3072.
The correct answer is  B. 3(2^{10})

vasu1104 · Answer

say distance is a

2^11 - 2^10 = a
a = 2^10

now x - 2^11 = 2^10
x = (2^10 ) * 3

If the distances between each pair of consecutive ticks are equal, wha

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