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Bunuel
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2a * 4b * 8C = 64abc

so 10*10*10 = 1000 Answer E
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Bunuel
If \(2a = 4b = 8c = 10\), then \(64abc =\)

(A) 64,000
(B) 16,000
(C) 8,000
(D) 4,000
(E) 1,000

We see that 64abc = (2a)(4b)(8c) = (10)(10)(10) = 1,000

Answer: E
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Bunuel
If \(2a = 4b = 8c = 10\), then \(64abc =\)

(A) 64,000
(B) 16,000
(C) 8,000
(D) 4,000
(E) 1,000


We can write 64abc=2a*4b*8c

Now substituting the value of 2a, 4b and 8c from the given data, we have

64abc=10*10*10=1000

Ans. E
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Bunuel
If \(2a = 4b = 8c = 10\), then \(64abc =\)

(A) 64,000
(B) 16,000
(C) 8,000
(D) 4,000
(E) 1,000

It's given that 2a=4b=8c=10. It means that all these terms have equal value which is 10.

we are asked to find out the value of 64abc = 32*2*abc=8*4*2*abc= 2a*4b*8c=10*10*10= 1000

Thus the best answer is E.
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64abc = 2a*4b*8c
10*10*10 = 1000

Ans E
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