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03 Jun 2018, 12:46
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
69% (01:42) correct
31%
(01:53)
wrong
based on 346
sessions
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Date
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All first-year students at Red State University must take calculus, English composition, or both. If half of the 2,400 first-year students at Red State University take calculus and half do not, and one-third of those who take calculus also take English composition, how many students take English composition?
A) 400
B) 800
C) 1,200
D) 1,600
E) 2,000
A) 400
B) 800
C) 1,200
D) 1,600
E) 2,000
alldaytestprep
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Joined: 08 May 2018
Last visit: 24 Apr 2023
Posts: 98
Given Kudos: 1
Affiliations: All Day Test Prep
Location: United States (IL)
Schools: Booth '20 (A)
GMAT 1: 770 Q51 V49
GRE 1: Q167 V167
GPA: 3.58
Expert reply
03 Jun 2018, 13:08
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Bunuel
See file below for setup. The key is recognizing that the number of students in No Calculus/No English is zero. After that, it's simply knowing which box you're trying to solve for and plugging in.
Answer: D
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Screen Shot 2018-06-03 at 3.06.45 PM.png [ 529.15 KiB | Viewed 9437 times ]
03 Jun 2018, 23:40
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Solution
Given:
- • Out of 2400 first year students, everyone must take either Calculus, or English Composition, or both
• Half of all the students take Calculus, half do not
• One-third of those who take Calculus also take English Composition
To find:
- • The number of students take English Composition
Approach and Working:
As one-third of those who take Calculus also take English Composition, we can say
- • Number of students take both Calculus and English Composition = \(\frac{1}{3} *(\frac{1}{2} * 2400) = 400\)
- • Number of students who take English Composition only = \(\frac{1}{2} * 2400 = 1200\)
• Therefore, the total number of students taking English Composition = 400 + 1200 = 1600
Hence, the correct answer is option D.
Answer: D
