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=>

1, 6, 11, 16, 21 and 26 have remainder 1 when they are divided by 5.
2, 7, 12, 17, 22 and 27 have remainder 2 when they are divided by 5.
3, 8, 13, 18, 23 and 28 have remainder 3 when they are divided by 5.
4, 9, 14, 19, 24 and 29 have remainder 4 when they are divided by 5.
5, 10, 15, 20, 25 and 30 have remainder 0 when they are divided by 5.

The sum of the remainders is
1*6 + 2*6 + 3*6 + 4*6 + 0*6 = ( 1 + 2 + 3 + 4 + 0 ) * 6 = 60.

Therefore, the answer is C.

Answer: C
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What is the sum of the remainders when the first 30 positive integers are divided by 5?

A. 50
B. 55
C. 60
D. 65
E. 70

For the first 30 positive integers, we can divide them into 6 sets of 5 consecutive integers, with the last integer in each set a multiple of 5. For example, the first set is {1, 2, 3, 4, 5}.

Let’s divide each integer in the first set by 5: 1/5 = 0 R1 , 2/5 = 0 R2, 3/5 = 0 R3, 4/5 = 0 R4, and 5/5 = 1 R0. The first set has remainders of 1, 2, 3, 4, and 0, and the sum of these remainders is 1 + 2 + 3 + 4 + 0 = 10.

The second set of numbers is {6, 7, 8, 9, 10}, and the pattern of remainders is identical to that of the first set, so the sum of the remainders for the second set will also be 10. In fact, each of the remaining sets of 5 numbers will have the same pattern of remainders and the same sum.

Since there are 6 sets, and since each set has a remainder sum of 10, the sum of all the remainders is 10 x 6 = 60.

Answer: C
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What is the sum of the remainders when the first 30 positive integers are divided by 5?

Remainders of the number from 1 to 53 when divided by 5 will
    ✤ Repeat in the pattern (1,2,3,4,0) and will
    ✤ Repeat \(\frac{30}{5}\) = 6 times


Remainder of 1 by 5 = 1
Remainder of 2 by 5 = 2
Remainder of 3 by 5 = 3
Remainder of 4 by 5 = 4
Remainder of 5 by 5 = 0

=> Sum of Remainders of numbers from 1 to 30 when divided by 5 = 6 * ( 1 + 2 + 3 + 4 + 0) = 6 * 10 = 60

So, Answer will be C
Hope it helps!

Watch the following video to MASTER Remainders

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