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Bunuel
A full bottle contains 40% oil, 20% vinegar, and 40% water. The bottle is poured into a larger bottle, four times as big as original. The remaining space in the larger bottle is then filled with water. If there was 8 ml of oil in the original bottle, how much of water is in the final mixture?

A. 8 ml
B. 20 ml
C. 60 ml
D. 68 ml
E. 80 ml

Let x be the size of original bottle
1. Ratio of oil, vinegar and water are in 2:1:2.
2. Given: 8 ml of oil in original bottle.
So,
2/5 * x = 8, which gives x=20
3. Given: Larger bottle = 4 * original bottle
i.e Larger bottle = 4 * x = 4 * 20 = 80

So, 20 ml poured in 80 ml of bottle. That leaves 80-20 = 60 ml remaining
Given, remaining space in the larger bottle is then filled with water

i.e. 60 ml filled in large bottle with water.

Question asked is: water in final mixture, which is 8 ml(as poured from original bottle previously) + 60 ml (highlighted above)
Equals 68 - option (D)

Please let me know, if this is correct ! Kindly publish the answer asap
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I am getting a D.

Following is my approach :
Let the volume of the bottle be X ml;
Oil (40%) = 8ml, we get 40x/100 =8; x = 20ml
Water (40%) would be 8 ml -------(i)

four times size of the bottle would be 4x = 4 * 20 =80 ml.
Space remaining after pouring 20 ml = 80 - 20 =60ml-----(ii)

Adding (i) and (ii);
60 + 8 = 68ml.


Please kudo if that helped.

looking forward to a faster approach though.
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Please see attached file below
The correct answer is (D) 68 ml.
Attachments

Bottle x and 4x.png
Bottle x and 4x.png [ 31.65 KiB | Viewed 8731 times ]

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Bunuel
A full bottle contains 40% oil, 20% vinegar, and 40% water. The bottle is poured into a larger bottle, four times as big as original. The remaining space in the larger bottle is then filled with water. If there was 8 ml of oil in the original bottle, how much of water is in the final mixture?

A. 8 ml
B. 20 ml
C. 60 ml
D. 68 ml
E. 80 ml

Oil:Vinegar:water:total

4:2:4:10

4x = 8 , x = 2

then the ratios will be 8:4:8:20

Since the larger bottle is 4 times it will 20*4 = 80

80 - 20 = 60 water that needs to be added.

Previously there was 8 ml water and now we added 60 to fill the remaining so 60 + 8 = 68

Answer choice D
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The two pieces of information which are linked to each other are the percentage of oil and the actual quantity of oil in the original bottle, since both represent the same quantity.

Essentially, 40% = 8 ml. This helps us understand that 100% = 20 ml. In turn, this helps us understand the quantities of the other liquids –> there is 4 ml of Vinegar and 8 ml of Water.

The volume of the larger bottle is 4 times as big as the original bottle. Therefore,
Volume of larger bottle = 4*20 = 80 ml.
Of this 80 ml, 20 ml represents the mixture from the original bottle. Question says that the remaining space is filled with water. So 60 ml of water must have been poured to fill the larger bottle completely.

In all, total volume of water in the final mixture = 8 ml (from the original bottle) + 60 ml (from the one that was poured to fill the large bottle) = 68 ml.
The correct answer option is D.

In a question like this, it’s important to find out that one important information that acts like a key and opens the doorway to solving the question. In this case, it was the relationship between the percentage and the absolute value of the volume of oil in the original bottle.

Hope that helps!
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40% oil is 8 ml, meaning 40% of water is also 8 ml and 20% vinegar is 4 ml. = 20ml is small bottle's volume;
20 * 4 = 80 is the volume of the 4 times larger new bottle; and water in the new bottle is: amount of new water + amount of old water = 60 + 8 = 68.
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Deconstructing the Question

The original bottle contains \(40\%\) oil, \(20\%\) vinegar, and \(40\%\) water.

We are told that the oil amount is \(8\) ml, so we first find the total volume of the original bottle.

Then the mixture is poured into a bottle that is \(4\) times as large, and the remaining space is filled with water.

Step-by-step

Let the original volume be \(V\).

Since oil is \(\frac{2}{5}\) of the bottle,

\(\frac{2}{5}V = 8\)

So

\(V = 8 \cdot \frac{5}{2} = 20\)

Thus the original bottle contains \(20\) ml.

Original water is

\(\frac{2}{5}\cdot 20 = 8\)

The larger bottle has capacity

\(4 \cdot 20 = 80\)

So the added water is

\(80 - 20 = 60\)

Final water amount is

\(8 + 60 = 68\)

Answer: D
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