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Bunuel
If the sum of 6 consecutive integers is x, which of the must be true?

I. x is even
II. x is odd
III. x is a multiple of 3

A) I only
B) II only
C) III only
D) I and III
E) II and III


Test the numbers :

x = 2 +3 + 4 + 5 + 6 + 7 =27

x = 3 + 4 + 5 + 6 + 7 + 8 = 33

So, x is odd and multiple of 3.

The best answer is E.
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Bunuel
If the sum of 6 consecutive integers is x, which of the must be true?

I. x is even
II. x is odd
III. x is a multiple of 3

A) I only
B) II only
C) III only
D) I and III
E) II and III

OA: E
Let first integer be \(a\)
Then list of 6 consecutive integers would be \(a, a+1,a+2,a+3,a+4,a+5\)
Sum of first n terms of an AP: S =(n/2)[2a + (n- 1)d]
here d = 1 and n =6,
Sum of first 6 terms of AP: S =\((\frac{6}{2})*[2a + (6- 1)1]=3(2a+5)\)
So S is multiple of 3.
\(2a\) is always even,\(S =odd(even+odd)=odd*odd =odd\)
and S is also odd.
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Bunuel
If the sum of 6 consecutive integers is x, which of the must be true?

I. x is even
II. x is odd
III. x is a multiple of 3

A) I only
B) II only
C) III only
D) I and III
E) II and III

six consecutive int will always have 3 odd and 3 even
odd+odd=even
we are now left with all even and an odd
and even +odd=odd
so x will always be odd !!

also , six consecutive int will always have one int that is a multiple of 3 , and any number*(3p) will be a multiple of 3

so E
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Bunuel
If the sum of 6 consecutive integers is x, which of the must be true?

I. x is even
II. x is odd
III. x is a multiple of 3

A) I only
B) II only
C) III only
D) I and III
E) II and III

The sum of 6 consecutive integers will be the sum of 3 odd numbers and 3 even numbers, which results in an odd sum.

The sum of any 3 consecutive integers is a multiple of 3. Since 6 consecutive integers consist of two (disjoint) sets of 3 consecutive integers, thus the sum of 6 consecutive integers is also a multiple of 3.

Answer: E
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Bunuel
If the sum of 6 consecutive integers is x, which of the must be true?

I. x is even
II. x is odd
III. x is a multiple of 3

A) I only
B) II only
C) III only
D) I and III
E) II and III

x=3 times the odd sum of 2 middle odd-even integers
so x must be odd and a multiple of 3
E
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