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22 Aug 2018, 01:45
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
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Question Stats:
88% (00:44) correct
12%
(00:59)
wrong
based on 117
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[Math Revolution GMAT math practice question]
Alice, Bob, Cindy, Dave and Eddie joined a three-person-a-side basketball tournament. In how many ways can be the three starters be chosen?
A. 5
B. 6
C. 8
D. 9
E. 10
Alice, Bob, Cindy, Dave and Eddie joined a three-person-a-side basketball tournament. In how many ways can be the three starters be chosen?
A. 5
B. 6
C. 8
D. 9
E. 10
22 Aug 2018, 05:39
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MathRevolution
The order in which we select the 3 starters does not matter.
For example, selecting Alice then Cindy and then Dave to be the starters is the SAME as selecting Cindy then Dave and then Alice to be the starters.
Since order does not matter, we can use COMBINATIONS
We can select 3 players from 5 players in 5C3 ways
5C3 = (5)(4)(3)/(3)(2)(1) = 10
Answer: E
RELATED VIDEO FROM OUR COURSE
22 Aug 2018, 10:15
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MathRevolution
Out of 5 , we need 3
which is
5c3 = \(\frac{5*4}{2}\) = 10
