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Ratio of circumference of inner circle to the outer circle is equal to the ratio of radius of inner circle to the outer circle

r= \(\frac{1}{5}\)R= \(\frac{r}{R}\)= \(\frac{1}{5}\)

Answer: B.
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Bunuel

Note: Figure not drawn to scale.

If the radius of the inner circle is one-fifth of the radius of the outer circle, what is the ratio of the circumference of the inner circle to that of the outer circle?

A. 1 : 25
B. 1 : 5
C. 2 : 5
D. 5 : 2
E. 5 : 1


Attachment:
image001.jpg


given R = 5r

c1 = 2pir
c2 = 2piR
substituting the value
\(\frac{c1}{c2}\) =\(\frac{1}{5}\)
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Circumference varies linearly with radius

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Bunuel

Note: Figure not drawn to scale.

If the radius of the inner circle is one-fifth of the radius of the outer circle, what is the ratio of the circumference of the inner circle to that of the outer circle?

A. 1 : 25
B. 1 : 5
C. 2 : 5
D. 5 : 2
E. 5 : 1


Attachment:
image001.jpg

We can let the radius of the inner circle = 1, thus the radius of the outer circle = 5. Furthermore, the circumferences of the inner and outer circles are 2π and 10π, respectively; thus the ratio is

2π/10π = ⅕ , or 1 : 5.

Alternate Solution:

The ratio of the two radii is 1 : 5. Since the circumference of a circle is a linear function of the radius, then the ratio of the circumferences of the two circles remains unchanged from that of the radii, and it is still 1 : 5.

Answer: B
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