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Bunuel
If \(5^{k + 1} = 2,000\), what is the value of \(5^k + 1\)?

(A) 399
(B) 401
(C) 1,996
(D) 2,000
(E) 2,001


\(5^{k+1} = 2000\)
\(5^{k+1} = 2^45^3\)
\(5^k5 = 5^32^4\)
\(5^k = 5^22^4\)

\(5^2 = 25\)
\(2^4 = 16\)

25*16 = 400

\(5^k = 400\)

\(5^k\) + 1 = 401.

The best answer is B.
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Bunuel
If \(5^{k + 1} = 2,000\), what is the value of \(5^k + 1\)?

(A) 399
(B) 401
(C) 1,996
(D) 2,000
(E) 2,001
Answer is B
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Bunuel
If \(5^{k + 1} = 2,000\), what is the value of \(5^k + 1\)?

(A) 399
(B) 401
(C) 1,996
(D) 2,000
(E) 2,001


\(5^{k + 1} = 2,000\),

5^k . 5 = 2000,
5^k = 400

Therefore, 5^k + 1 = 400 + 1 = 401.

Hence answer is B.
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KSBGC
Bunuel
If \(5^{k + 1} = 2,000\), what is the value of \(5^k + 1\)?

(A) 399
(B) 401
(C) 1,996
(D) 2,000
(E) 2,001


\(5^{k+1} = 2000\)
\(5^{k+1} = 2^45^3\)
\(5^k5 = 5^32^4\)
\(5^k = 5^22^4\)

\(5^2 = 25\)
\(2^4 = 16\)

25*16 = 400

\(5^k = 400\)

\(5^k\) + 1 = 401.

The best answer is B.


Where do you take the value: m]5^k5 = 5^32^4[/m] ? Can somebody explain?
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Hi,

Can somebody explain how 5^(k+1) becomes 5^k 5 ?
Thank you!
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