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28 Aug 2018, 08:35
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
61% (02:02) correct
39%
(02:21)
wrong
based on 102
sessions
History
Date
Time
Result
Not Attempted Yet
How much minimum marks is required to pass the examination?
I. Student A secured 38% in the examination and failed by 8 marks. Student B secured 42% marks in the same examination and got 12 more than the minimum pass marks.
II. Student A secured 35% of the total marks in the examination and failed by 23 marks. If he had secured 25 more marks his percentage of marks would have been 40%.
III. A student will be declared passed, if he secures 39.60% of the total marks.
(a) Any two of them
(b) Only I
(c) III and either I or II
(d) Either I or II
(e) None of these
I. Student A secured 38% in the examination and failed by 8 marks. Student B secured 42% marks in the same examination and got 12 more than the minimum pass marks.
II. Student A secured 35% of the total marks in the examination and failed by 23 marks. If he had secured 25 more marks his percentage of marks would have been 40%.
III. A student will be declared passed, if he secures 39.60% of the total marks.
(a) Any two of them
(b) Only I
(c) III and either I or II
(d) Either I or II
(e) None of these
28 Aug 2018, 10:00
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alok019
Let's analyze each of the statements.
Let 'x' be the full marks .
I. Student A scored 38% of x or, 0.38x. He failed by 8 marks. So, minimum pass mark=0.38x+8------------(a)
Student B scored 42% of x or, 0.42x. He scored 12 more than the minimum pass mark. Or, 0.42x=minimum pass mark+12 Or, minimum pass mark=0.42x-12-------(b)
We can find out the value of x , subsequently the minimum pass mark by solving (a) and (b).
Since answer options don't require exact value of minimum pass mark, hence exact computation isn't required.
II. With the similar reasoning, minimum pass mark of student A=0.35x+23
If he had secured 25 more marks his percentage of marks would have been 40%. Implies that 0.35x+25=0.40x
We can find out the value of x , subsequently the minimum pass mark by solving the above equation.
III. Minimum pass mark=39.60% of x=39.60x , where value of x is unknown.
So, minimum pass mark can't be determined.
So either st I or st II will give us the minimum pass mark.
Ans. (D)
P.S:- Dear Moderators,I would request to place this question at its correct address i,e, PS forum.
