Which of the following is equivalent to (8! + 9!)/10!?

Question

Which of the following is equivalent to  \frac{8!+9!}{10!} ?

A. 1/72
B. 9/100
C. 1/9
D. 9/10
E. 17/10

PKN · Answer

Express all the terms in terms of the lowest magnitude of factorial,

\frac{8!+9!}{10!} = \frac{8!+8!*9}{8!*9*10} = \frac{8!(1+9)}{8!*9*10} = \frac{8!*10}{8!*9*10} 
= \frac{1}{9}

Ans. (C)

Chethan92 · Answer

= (8!+9*8!)/10!

= 8!(1+9)/10!

= 10/10*9

= 1/9

C is the answer

Posted from my mobile device

Akash720 · Answer

\frac{8!+9!}{10!}

\frac{8!(1+9)}{10!}

Reducing 8! -->  \frac{10}{10*9}

\frac{1}{9}

Hence C

aggvipul · Answer

Take 8 factorial common from numerator, this will render
 \frac{8!(1+9)}{10*9*8!}

=  \frac{1}{9} 
Option C

Abhishek009 · Answer

\frac{8!+9!}{10!}

=  \frac{8!+8!*9}{8!*9*10}

=  \frac{8! ( 1 + 9)}{8!(9*10)}

=  \frac{8!*10}{8!(9*10)}

=  \frac{1}{9} , Answer must be (C)

JeffTargetTestPrep · Answer

Factoring out 8! from the numerator and denominator, we have:

8!(1 + 9)/

Canceling the 8!, we have:

10/90

1/9

Answer: C

Prep Toolkit