If the length, l, of a rectangle is six times the width, w, of the sam

Question

If the length, l, of a rectangle is six times the width, w, of the same rectangle, which of the following is the diagonal of the rectangle in terms of w?

A.  \sqrt{6}w

B.  \sqrt{7}w

C. 7w

D.  \sqrt{37}w

E. 37w

saurabh9gupta · Answer

So the 
Length- 6w
Width- w

Diagonal d =?

d^2 = (6w)^2 + (w)^2

So D

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arjunnath · Answer

Length = 6w
Width = w

Using Pythagoras,

(6w)^2 + (w)^2 = d^2
36w^2 + w^2 = d^2
37w^2 = d^2
Hence, 
d=  w

Answer is D

ScottTargetTestPrep · Answer

The length of the rectangle is 6w, and the width is w. To determine the length of the diagonal, we can use the Pythagorean theorem, and we have:

(6w)^2 + w^2 = d^2

36w^2 + w^2 = d^2

37w^2 = d^2

w√37 = d

Answer: D

loneo3006 · Answer

Hi All,
here is the mistake I've maid, could you explain me why I was wrong?

I got to the part of writting down the following : w²+(6w)²=d²
So I decided to square root everything and did squrt(w²+(6w)²=d²) --> w+6w=d --> 7w=d

Of course there was a trap answer with 7w (C)

So I understand your reasoning through the 36w but I don't get why I am not allowed to square root everything.

Thanks for your help guys.

If the length, l, of a rectangle is six times the width, w, of the sam

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If the length, l, of a rectangle is six times the width, w, of the sam

Prep Toolkit

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