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rahul16singh28
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What is the solution of 4x - 4 = 3 * 2x? Updated on: 09 Sep 2018, 22:12
Originally posted by rahul16singh28 on 09 Sep 2018, 22:02.
Last edited by Bunuel on 09 Sep 2018, 22:12, edited 1 time in total.
Renamed the topic and edited the question.
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Question Stats:

83% (01:15) correct 17% (01:16) wrong based on 35 sessions

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What is the solution of 4√x - 4 = 3 * 2√x?

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What is the solution of 4x - 4 = 3 * 2x? 10 Sep 2018, 01:18
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rahul16singh28
What is the solution of 4√x - 4 = 3 * 2√x?

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4√x - 4 = 3 * 2√x
\(4\sqrt{x}-6\sqrt{x}=4.................-2\sqrt{x}=4\)
square both sides..
\(4x=16...............x=4\)

4√x - 4 = 3 * 2√x...........- 4 = 2√x....
Only possible if x is perfect square

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What is the solution of 4x - 4 = 3 * 2x? 10 Sep 2018, 07:28
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rahul16singh28
What is the solution of 4√x - 4 = 3 * 2√x?

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\(4√x - 4 = 3 * 2√x\)

Or, \(4√x - 4 = 6√x\)

So, \(2√x = - 4\)

Or, \(4x = 16\) {Squaing both sides}

Or, \(x = 4\), Answer must be (D)
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What is the solution of 4x - 4 = 3 * 2x? 11 Sep 2018, 17:49
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rahul16singh28
What is the solution of 4√x - 4 = 3 * 2√x?

1. 1
2. 2
3. 3
4. 4
5. 5
\(4√x - 4 = 3 * 2√x\)

Or, \(4√x - 4 = 6√x\)

So, \(2√x = - 4\)

Or, \(4x = 16\) {Squaing both sides}

Or, \(x = 4\), Answer must be (D)
Show more

Hi Abhishek009, thanks for the lucid explanation but I realised on plugging in 4 into the equation. The LHS does not equal the RHS. Why is this

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What is the solution of 4x - 4 = 3 * 2x? 11 Sep 2018, 19:27
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Kem12
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rahul16singh28
What is the solution of 4√x - 4 = 3 * 2√x?

1. 1
2. 2
3. 3
4. 4
5. 5
\(4√x - 4 = 3 * 2√x\)

Or, \(4√x - 4 = 6√x\)

So, \(2√x = - 4\)

Or, \(4x = 16\) {Squaing both sides}

Or, \(x = 4\), Answer must be (D)

Hi Abhishek009, thanks for the lucid explanation but I realised on plugging in 4 into the equation. The LHS does not equal the RHS. Why is this

Posted from my mobile device
Show more

Hi Kem12,
This question is flawed.

Given, \(4√x - 4 = 3 * 2√x\)

Or, \(4√x - 4 = 6√x\)

So, \(2√x = - 4\)
Divide both sides by -2, we have
\(\sqrt{x}=-2\)

Notice that \(\sqrt{f(x)}\) can't be negative for all \(x\in \mathbb{R}\).

Therefore, NO SOLUTION.
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What is the solution of 4x - 4 = 3 * 2x? 11 Sep 2018, 21:02
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PKN
Kem12
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What is the solution of 4√x - 4 = 3 * 2√x?

1. 1
2. 2
3. 3
4. 4
5. 5

\(4√x - 4 = 3 * 2√x\)

Or, \(4√x - 4 = 6√x\)

So, \(2√x = - 4\)

Or, \(4x = 16\) {Squaing both sides}

Or, \(x = 4\), Answer must be (D)

Hi Abhishek009, thanks for the lucid explanation but I realised on plugging in 4 into the equation. The LHS does not equal the RHS. Why is this

Posted from my mobile device

Hi Kem12,
This question is flawed.

Given, \(4√x - 4 = 3 * 2√x\)

Or, \(4√x - 4 = 6√x\)

So, \(2√x = - 4\)
Divide both sides by -2, we have
\(\sqrt{x}=-2\)

Notice that \(\sqrt{f(x)}\) can't be negative for all \(x\in \mathbb{R}\).

Therefore, NO SOLUTION.
Show more

You are right. This is a poor quality question.

Topic is locked.

This Question is Locked Due to Poor Quality
Hi there,
The question you've reached has been archived due to not meeting our community quality standards. No more replies are possible here.
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