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chetan2u, assuming we have the missing number for this diameter, what exactly would be the theory behind the working? would we have to use parallel lines for this?
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using similar triangles, we get that AB can be split into two halves, 6 and 6

with the radius as 6 root 3 and the one half of the chord as 6, we get the height of the triangle formed as 6 root 2.
However, from this i am unable to calculate the angle of the triangle, needed to calculate the length of the arc.
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Bunuel
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chetan2u, assuming we have the missing number for this diameter, what exactly would be the theory behind the working? would we have to use parallel lines for this?
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Hi Bunuel is the radius \(6 \sqrt{2}\) or \(6 \sqrt{3}\)? because with the given radius, that is \(6 \sqrt{3}\), i am unable to calculate the angle using trig
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what is the length of the arc ACB?


A. 24π
B. 18π
C. 16π
D. 12π
E. 8π


I solve this one with POE, the diameter of the circle is 12 root 3, and AB is 12, that means that the arc acb has to be smaller then the semicircle arc, because the diameter is the largest line segment in circle,if we move either way the value of the segment will get smaller.

now the total circmfrnc is 2pir= 2*pi*6root3=12root3*pi.then we will only be left with option E.
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