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Sub 505 (Easy)|   Algebra|   Exponents|            
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Bunuel
If \((7^{\frac{3}{4}})^n = 7\), what is the value of n?


(A) 1/3

(B) 2/3

(C) 4/3

(D) 5/3

(E) 6/3
\((7^{\frac{3}{4}*\frac{4}{3}}) = 7\), Hence Answer must be (C)
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(7^3/4)^n=7, what is the value of n?

(7^3/4)^n=7
or,7^(3/4*n) = 7^1
so,(3/4)*n = 1
n = 4/3

correct answer C
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Bunuel
If \((7^{\frac{3}{4}})^n = 7\), what is the value of n?


(A) 1/3

(B) 2/3

(C) 4/3

(D) 5/3

(E) 6/3

Simplifying, we have:

7^(3n/4) = 7^1

3n/4 = 1

n = 4/3

Answer: C
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7^(3/4)^n = 7^1
Then 3n/4 = 1
n=4/3
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