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pushpitkc
If the area of a circle is \(64\pi\), then the diameter of the circle is

(A) \(8\)
(B) \(16\)
(C) \(32\)
(D) \(8\pi\)
(E) \(16\pi\)
\(πr^2 = 64π\)

So, \(r = 8\)

Thus, Diameter of the circle must be \(2*r = 16\) ; Answer must be (B)
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pushpitkc
If the area of a circle is \(64\pi\), then the diameter of the circle is

(A) \(8\)
(B) \(16\)
(C) \(32\)
(D) \(8\pi\)
(E) \(16\pi\)
Solution:

Letting r be the radius of the circle, we have:

πr^2 = 64π

r^2 = 64

r = 8

Since the radius of the circle is 8, the diameter of the circle is 16.

Answer: B
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If the area of a circle is 64*pi, then the diameter of the circle is

Area = pi*r^2
64*pi = pi*r^2
r=8

Diameter = 16

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